Transistor past paper question

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chaosdestro0

Joined Apr 30, 2011
10
Not sure if this is correct, there is no way to be sure as the mark scheme has no diagram ( It's £3 and does not even come with diagrams for graphs )
 

jegues

Joined Sep 13, 2010
733
Not sure if this is correct, there is no way to be sure as the mark scheme has no diagram ( It's £3 and does not even come with diagrams for graphs )
Well the relationship between the base current and the collector current is,

\(I_{c} = \beta I_{b}\)

so one would expect a linear graph like you've drawn, with the vertical and horizontal intercept passing through the origin.
 
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