The time constant is 1mS. The voltage on the cap will theoretically never reach 100V, because, as Papabravo says, it will approach that value asymptotically. In five time constants, it will charge to 99.326V, which is generally accepted as fully charged.Papabravo is correct. The initial steady-state voltage across the capacitor is 0V, however the voltage across the capacitor will increase at a rate of 100kV per second (no longer in steady-state conditions) so every second the voltage across the capacitor would in theory increase by 100kV. It would in fact reach steady state conditions of 100V across the capacitor very quickly; 1ms if I have done my maths right.
Dave
You are correct about the RC time constant and the fact that the voltage across the capacitor approaches the 100V source voltage asymptotically. The general point I was making was that the rate of rise of the voltage across the capacitor is the intermediate transition from the initial steady-state 0V to a steady-state ~100V. This is a simplification of the reality but demonstrates the point raised in the OP.The time constant is 1mS. The voltage on the cap will theoretically never reach 100V, because, as Papabravo says, it will approach that value asymptotically. In five time constants, it will charge to 99.326V, which is generally accepted as fully charged.
Thread starter | Similar threads | Forum | Replies | Date |
---|---|---|---|---|
K | Identifying transients | Analog & Mixed-Signal Design | 3 | |
Transients in capacitors. | General Electronics Chat | 2 | ||
P | scr causes transients | Power Electronics | 4 | |
Being Frugal: Harvesting Energy from Transients? | Analog & Mixed-Signal Design | 15 | ||
Help me: transients and current ratio calculations | Homework Help | 2 |
by Jake Hertz
by Jake Hertz
by Jake Hertz
by Duane Benson