Hello all,
I'm trying to get the transfer function of this om amp example:
Combining the capacitor and resistor in series gives \(\frac {1+sRC}{sC}=Z1\)
Usually I would use KCL but for this particular example it would need a load on the output to work out an equation. For example, if I put a load \(Z2\) connected between \(Vout\) and ground the transfer function can than be solved and would come out like this \(\frac {Vout} {Vin} = \frac {Z2} {Z2-Z1}\)
This om amp
has the transfer function \(\frac {Vout} {Vin} = \frac {1} {sRC}\)
My question is why is it necessary to have a load on the output of the first om amp example? Is it because there is no reference to ground?
Please excuse me if I'm not seeing the obvious.
I'm trying to get the transfer function of this om amp example:
Combining the capacitor and resistor in series gives \(\frac {1+sRC}{sC}=Z1\)
Usually I would use KCL but for this particular example it would need a load on the output to work out an equation. For example, if I put a load \(Z2\) connected between \(Vout\) and ground the transfer function can than be solved and would come out like this \(\frac {Vout} {Vin} = \frac {Z2} {Z2-Z1}\)
This om amp
has the transfer function \(\frac {Vout} {Vin} = \frac {1} {sRC}\)
My question is why is it necessary to have a load on the output of the first om amp example? Is it because there is no reference to ground?
Please excuse me if I'm not seeing the obvious.