Transfer function with two nodes

Discussion in 'Homework Help' started by Schoppy, Jul 8, 2014.

  1. Schoppy

    Thread Starter New Member

    Jul 7, 2014
    I need help starting it, I don't want the whole thing I just want a little nudge, I'm assuming we will do a superposition with node voltage but I have to get it into terms of V_in. V_out is obviously easy but I'm struggling to get going.
  2. anhnha

    Well-Known Member

    Apr 19, 2012

    Can you calculate the voltage at the node where two resistors and one capacitor are jointed?

    Let's call that voltage is V1.
    You need to express V1 = Z1*Vin
    Then you express Vout in terms of V1.
    Vout = Z2*V1

    From that we have: Vout = Z2*V1 = Z2*(Z1*Vin) = Z1*Z2*Vin
    => Vout/Vin = Z1*Z2
  3. MrAl

    Distinguished Member

    Jun 17, 2014

    Yes combining impedances is one way to handle this, combining the last resistor and last capacitor with the first capacitor to form a voltage divider to get v1, but what about simple nodal analysis? That's a general way to handle these kinds of networks.
    Then there's also Thevenin and Norton.
  4. Schoppy

    Thread Starter New Member

    Jul 7, 2014
    Yea I was able o solve it using nodal analysis it just took me some time to remember how to do it. Thanks guys!