http://www.electronics-tutorials.ws/filter/fil51.gif

The transfer function of this filter is:

H(jω)=(jωR2C1) / [(jωR2C2+1)(jωR1C1+1)]

Shouldn't the transfer function include the gain R2/R1 and * (-1);

H(jω)= - (R2/R1) * [(jωR2C1) / [(jωR2C2+1)(jωR1C1+1)]] ?

The transfer function of a low pass filter is:

H(jω)= -R2/R1 * 1/(jωR2C2)

The transfer function of a high pass filter is:

H(jω) - jωR2C1 / (jωR1C1+1)

Shouldn't the transfer function of the high pass filter also include gain;

H(jω) - (R2/R1) * [jωR2C1 / (jωR1C1+1)] ?

So can I find the transfer function of the band pass filter by multiplying the transfer function of the low pass and high pass filter, and the gain;

H(jω)low * H(jω)high * - (R2/R1) ?

Finally, how do I find the impedance input and output of this bandpass filter?