Thevenin equivalent and calculating I

Thread Starter

uraza

Joined May 24, 2014
4
I am studying for an exam and in this old exam: http://www.eit.lth.se/fileadmin/eit/courses/etia01/1213/maj12.pdf

Question 2c. Assume that the points p and p' are connected and the same for q and q'. What is the current I?

To me the answer should be I = V_th/R_th. Where V_th is the Thevenin equivalent voltage for the left circuit and same for R_th. This should then be I = 1.5V/15.

However, according to the answer it is I = 1.5V/(15+15).

Could anyone help me explain why this is?
 

Thread Starter

uraza

Joined May 24, 2014
4
Thank you! I got it now since they're in series. Didn't think I needed to look at the right circuit's resistance.
 
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