thevenin and norton rlc circuits

your answer is wrong.

for calculating Zth, how must you put the independient sources? if it is a voltage source you must put it as an open or a short circuit? and if it is an current source as in this case, how it is converted? open circuit or short circuit? answer this question first and then redraw the circuit and show us again. or even better calculate Zth from the new circuit. I hope this help you
 

The Electrician

Joined Oct 9, 2007
2,986
In post #19 you took the first step. Now simply solve the rest of the network to get the current in the 15 ohm resistor. Show your work, and if you've made any mistakes, we'll point them out.
 

Thread Starter

rents89

Joined Feb 5, 2009
14
yeh i was just wonderin if that first step i took was correct as someone in a previous post told me i was incorrect, so im in doubt atm...
 

The Electrician

Joined Oct 9, 2007
2,986
yeh i was just wonderin if that first step i took was correct as someone in a previous post told me i was incorrect, so im in doubt atm...
You didn't make a mistake. You need to have more confidence in your results, which you can achieve by double or triple checking.

Now you have two current sources, which you can add together. The total current drives the parallel combination of the three passive branches. Show your work; show the voltage you get at the top of the current sources, and finally show the current you get in the 15 ohm resistor.
 
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