Yes. So far so good.I hv tried my best here is the output....
For the Thevenin equivalent resistance(Rth) , all the voltage source short and current source open than I got Rth= (((R12||R3)+R4)||R5)+R6. Is it Okay?
It's not an unreasonable method to use for this one, though I would have used Nodal Analysis since you only have two non-trivial nodes and one of those is the value you want.For calculate Thevenin voltage source using superposition (is it the best (understandable) one?).
Okay, you are being sloppy with your notation. What is VR5 and what is Vref?2. For voltage source U5 :
Ref=R12||R3 then voltage on resister R5 by voltage divider rule
VR5 =R5/ (Ref+R4+R5) * U5
This looks correct, but the notation is making it hard to follow. You have R5 and then you have I R5. The space makes it look like these are two different quantities, one of which is the resistance R5. It's admittedly hard with just straight text when you don't have subscripts. A common option is to use an underscore to indicate a subscript, so I_R5. You also need to indicate the polarities of your quantities; is I_R5 the current going up or the current doing down through R5? It's pretty easy to figure out which you mean, but the reader (or grader) should have to figure out what you mean -- it's your job to make it clear what you mean.3. For current source I3:
Total parallel Ref= R12||R3|| (R5+R4)
Current on R5 by current divider rule I R5 = Ref/R5* I3
Then voltage on resister R5 VR5 (3)=R5*I R5
So the current from I4 can either go through R4 and back to the source or it can go through R5 and back to the source (without passing through any other components)?4. For current source I4:
Total parallel Ref= R4||R5
Current on R5 by current divider rule I R5 = Ref/R5* I4
Then voltage on resister R5 VR5 (4)=R5*I R5
You are actually quite close.So now Vth = VR5 (1)+ VR5 (2)+ VR5 (3)+ VR5(4).
I can find Norton current by ohm law I=Vth/Rth ..
I think there are mistakes please help me.
Try the following:help pls wth thevinin equivalent basic clear eg. RLC ccts
|Thread starter||Similar threads||Forum||Replies||Date|
|THEVENIN AND NORTON CIRCUIT DEPENDENT SOURCES ONLY||Homework Help||1|
|THEVENIN AND NORTON CIRCUIT||Homework Help||1|
|A||Help calculating Norton equivalent current and Thevenin Equivalent Resistance of a circuit||Homework Help||1|
|Up For Review: Thevenin and Norton Equivalent Circuits||AAC Contributors Forum||31|
|J||Help with Thevenin / Norton Equivalent||Homework Help||4|
by Jake Hertz
by Jake Hertz
by Robert Keim