Thevenin and norton circuits???????? pls help

Thread Starter


Joined Aug 1, 2006
could someone please solve this problem for me,i don't know where to start, any help would be great. thank you


Maybe it would be easier for someone to help you if you uploaded the image and posted the link. Good luck, I'm struggling on Thevenin a bit myself.


Joined Feb 24, 2006
The voltage source equivalent of 4A across 3 ohms is 12 Volts in series with 3 ohms. Now we can add 12 Volts plus 5 Volts to get 17 volts, and we can add 8 ohms and 3 ohms to get 11 ohms. So the Thevenin equivalent for Q6A is:

17 Volts in series with 11 ohms.

For Q6B the norton equivalent is 1.54... Amps across 11 Ohms