Is there any math to tell what the average temperature would be if you had for example a constant dc current of 60 VDC (20 AMPS MAX current from the source) running through a coil of wire with a resistance of 30 ohms?
Plenty of variables.The environment that the coil of wire exists in will determine how much heat is removed from the vicinity of the coil of wire and that will determine the average temperature. There are too many variables for there to be a simple formula, and you need to be more specific about the conditions surrounding the coil.
You are of course correct, but the TS did not posit a consistent set of numbers. I believed he was interested in pushing 20 amps through 30 Ω with whatever voltage was required.@Papabravo:
60V, 30Ω
I = V / R = 2A
P = VI = 120W
The correct formula for V and R is V^2 / R = 60^2 / 30 = 3600 / 30 = 120W
I think you can be pretty confident that it will be below 1085°C - the melting point of copper (although he didn't actually say it was copper wire) but it will definitely be below 3422°C (melting point of tungsten).one can tell with certainty that the temperature will be simply some value between absolute zero and infinity.
(2A)^2 x 30Ω = 120W(20 Volts)2×30 Ω=12,000 watts
Sure, you can model the heat loss as a function of temperature, and then the equilibrium temperature is where the heat loss equals the heat input. You generally need to iterate to solve for heat loss as a function of a guessed temperature, and then keep adjusting the guess until it all converges.Is there any math to tell what the average temperature would be if you had for example a constant dc current of 60 VDC (20 AMPS MAX current from the source) running through a coil of wire with a resistance of 30 ohms?
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