Can you state the problem in some wordprocessor or other program, then export as pdf or an image?432)330480(76X
XXX)3024
XXX)X_______
XXX)xx2808
XXX)xx2592
XXX)XX_________
XXX)XX0000
I don't understand what you are saying. Could you go through one of our faulty solutions point by point so we can understand?I had better make it clear that davebee's solution fails in the third line, i.e. the second subtraction.
Oh, and Ratch, your two published solutions also fall at the same hurdle. Sorry.
So then we have 1005 - 7*132 = 81 . bringing down the E = 8 gives 818, right?OK we are dividing a six digit number ABCDEF by a three digit number, GHI to get a quotient JKL
We are told J=7
Proceeding throught the long division:
GHI into ABC won't go so bring down D and move one place right.
GHI into ABCD goes 7 times.
We are told the product 7 times GHI is only three digits ie not more than than 999.
If G is 2 or greater then the product would have four digits.
So G=1
This also tells us that A = 1 since the maximum product 1HI times 7HL is 199 times 799 = 159001 and we don't show leading zeros.
So place 7 times 1HI under the 1BCDEF and do the subtraction.
We are told this results in a two digit remainder so bring down E to make three digits.
Wait a minute. Why or where does it say that particular partial division cannot have zero for a remainder? "6" appears a valid number as far as I can see. I observe no violation of the rules here.We are told this is not divisible by 1HI.
(Davebee's solution would make it divisible 6 times.)
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