Hello guys,
I am newbie here, and this id my first post.
Somebody suggested me to ask my question here.
Sorry but I have some problems calculating the the derivatives and integrals of sine waves in forms of sin^2 wt.
I have a circuit which it's input has the form of "Vmsinwt" I added a dc offset to it as Vdc, So the final input has the forms of (Vdc + Vmsinwt).
The output of my circuit when the input signal is as (Vdc + Vmsinwt) would be in forms of (Vc + Vmsinwt) where Vc is the peak amplitude of a sine wave too which of course is just equal to Vdc.
Now I want to square the said ouput and then take double derivative of it.
By squaring, we'll get this: (Vc + Vmsinwt)². But I can not go on to take this:
δ²/δt² (Vc + Vmsinwt)² .
I just can take the derivative for sinx and cosx, Not for Vmsin² wt.
So plz kindly can you help me out HOW to do it? what is the method of doing so and whats the result plz?
What if the input happens to be Vmcoswt?
Thanks a bunch
I am newbie here, and this id my first post.
Somebody suggested me to ask my question here.
Sorry but I have some problems calculating the the derivatives and integrals of sine waves in forms of sin^2 wt.
I have a circuit which it's input has the form of "Vmsinwt" I added a dc offset to it as Vdc, So the final input has the forms of (Vdc + Vmsinwt).
The output of my circuit when the input signal is as (Vdc + Vmsinwt) would be in forms of (Vc + Vmsinwt) where Vc is the peak amplitude of a sine wave too which of course is just equal to Vdc.
Now I want to square the said ouput and then take double derivative of it.
By squaring, we'll get this: (Vc + Vmsinwt)². But I can not go on to take this:
δ²/δt² (Vc + Vmsinwt)² .
I just can take the derivative for sinx and cosx, Not for Vmsin² wt.
So plz kindly can you help me out HOW to do it? what is the method of doing so and whats the result plz?
What if the input happens to be Vmcoswt?
Thanks a bunch
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