Sorry for the low quality image. The switches are at the top connecting the wires which connect the wires connecting the resistors and inductors. They open at t = 0. The values of the inductors pictured are 3mH on the left, and 6mH on the right. This problem is kind of confusing to me. The switches are open for t < 0 and close at t = 0. It seams that in both configurations, the resistance of the resistors is not an essential component for solving the problem which is to find V(t). But in this case, V(t) seams to be 0, except for the short time when the switch opens and there is a sudden impulse. So I went about solving the problem by finding the initial current through the inductors and then solving for the current as a function of time after for t >= 0 when the switches open. But there is no resistance, so I just get I(t) = Ioe^(-tR/L) = Io u(t), where u(t) is the unit step function. So to get the voltage, which it seams is equal to the voltage across either inductors over time. I use v(t) = L di(t)/dt. And here is where it gets funny, because normally this would just be 0, but we are after the impulse, and so we take the derivative also of the step function giving us the impulse function which is 0 everywhere except t = 0. So the answer I get is 3mH * 24 imp(t) A, which is 8X10^(-3) imp(t) volts. But I'm not sure I am doing this correctly. The book is very confusing, and the answer in the back of the book just says V(t) = 24 imp(t). If anyone can help clarify what is happening in this circuit and verify that the impulse is 24mVolts not just 24Volts, that would be much appreciated. I'm most confused about taking the derivative of the x*u(t), and especially about the nature of the currents I1(t) and I2(t), both positive and heading towards each other, and constant for all of t > 0.