I agree but I was just pointing out that 200 is only a single three input And gate away...

 

Here's your solution, I think. It's an 8-bit binary counter, all you'd have to do is conect it's outputs to a series of logic AND and NOT gates to activate the output signal you want when the counter reaches 200. Let me know if you need help with that too.

 

You might be better off just to buy a totalizer off ebay, you just need the version that has a settable contact count and an output when the count is reached.
Ebay 251094838148
Max.

 

200 is fairly easy with an 8 bit counter and a few And gates. 200 == 11001000 in binary so And the 8th, 7th 4th bits.

A power of two means that you can let the counter free-run and pick off a particular output bit as the signal to the latch. You can then also just reset it to zero using a power-on-reset circuit.

 

Sigh, yes, yes, yes and it's not really worth debating but it so happens that 200 lends itself to that as well with the addition or 1 more chip containing a 3 input and gate

 

Hey Maxheadroom, that looks like exactly what I need. Thanks for the help everybody, I think Im going to try maxheadrooms suggestion.

 

An 8-bit presettable down counter (like an HCF40103B) can do the job without external logic; but the switch would still need de-bouncing.
Datasheet:
http://www.st.com/web/en/resource/technical/document/datasheet/CD00003071.pdf

Debouncing: http://www.ganssle.com/debouncing.htm
http://www.eng.utah.edu/~cs5780/debouncing.pdf

You may also wish to re-set the countdown if a certain time period has elapsed?