Hello,
I am doing some self-study, but I don't have the benefit of a solutions manual, so sooner or later I knew I would run into a problem.
This problem is from the book:
Electronic Circuit Analysis and Design, 2nd Edition
William H. Hayt, Gerold W. Neudeck
ISBN: 978-0-471-12501-3
(Chapter 1, Problem 7)
A diode for which I_D = exp(33*V_D) - 1 [nA] is in series with a dc source of 0.5V. Sketch a curve of I_D vs. V_in, the voltage across the series combination, for the two possible battery polarities. Include both positive and negative values of V_in.
To solve this problem, I let I_D = 1mA, and solved for V_D, which came out to be 0.419.
The answer in the back of the book shows that that if +0.5V was used for the dc source, then the V_in vs. I_D would be (0.919, 1 mA), and for -0.5V it would be (-0.081, 1mA). (1 point on each curve given as the answer)
To get these answers: +0.5V + 0.419V = 0.919 and -0.5V + 0.419V = -0.081. I assume that this what was meant by "the voltages across the series combination, V_in".
But I can't make sense of it when I draw the circuit out. Because it would make more sense if it was +0.5V - 0.419V = 0.081V and -0.5V - 0.419V = -0.919V, with the dc source and the diode in series.
Can someone please help me make sense of this?
I am doing some self-study, but I don't have the benefit of a solutions manual, so sooner or later I knew I would run into a problem.
This problem is from the book:
Electronic Circuit Analysis and Design, 2nd Edition
William H. Hayt, Gerold W. Neudeck
ISBN: 978-0-471-12501-3
(Chapter 1, Problem 7)
A diode for which I_D = exp(33*V_D) - 1 [nA] is in series with a dc source of 0.5V. Sketch a curve of I_D vs. V_in, the voltage across the series combination, for the two possible battery polarities. Include both positive and negative values of V_in.
To solve this problem, I let I_D = 1mA, and solved for V_D, which came out to be 0.419.
The answer in the back of the book shows that that if +0.5V was used for the dc source, then the V_in vs. I_D would be (0.919, 1 mA), and for -0.5V it would be (-0.081, 1mA). (1 point on each curve given as the answer)
To get these answers: +0.5V + 0.419V = 0.919 and -0.5V + 0.419V = -0.081. I assume that this what was meant by "the voltages across the series combination, V_in".
But I can't make sense of it when I draw the circuit out. Because it would make more sense if it was +0.5V - 0.419V = 0.081V and -0.5V - 0.419V = -0.919V, with the dc source and the diode in series.
Can someone please help me make sense of this?