Pretty much. The "current flow" in a capacitor is due to the changing voltage across the capacitor: i(t) = C(dV/dt)OK I am new to electronics, but as I understand it a capacitor blocks dc and allows ac to pass.
Also I dont think caps act as a wire when charged do they?
Dont they charge and discharge so there would not be a steady flow of current. I am speculating but I hope someone can correct me.
Thinking of a DC application, then when the capacitor is charged, the voltage across the capacitor is constant, i.e. dv/dt = 0 and therefore i = 0. The situation changes for AC application, because the opposing plates of the capacitor are constantly charging and discharging, i.e. dv/dt /= 0 and therefore i /= 0.But, if the capacitor is charged and its still current flowing will the capacitor discharge or it will only discharge if the current stop flowing (if u disconnect the battery)
by Steve Arar
by Jake Hertz
by Jake Hertz