What is the avg value of square wavw form 3 cos 2t+ 4cos (2t+Pi/4)
M Thread Starter manprash Joined Apr 6, 2009 1 Apr 6, 2009 #1 What is the avg value of square wavw form 3 cos 2t+ 4cos (2t+Pi/4)
t_n_k Joined Mar 6, 2009 5,455 Apr 6, 2009 #2 Hello manprash, Welcome to the forum. This function is a sinusoidal one rather than a square wave function. It will have zero average value. It is the sum of two simple sinusoids each of which individually has a zero average.
Hello manprash, Welcome to the forum. This function is a sinusoidal one rather than a square wave function. It will have zero average value. It is the sum of two simple sinusoids each of which individually has a zero average.
jasperthecat Joined Mar 26, 2009 20 Apr 6, 2009 #3 The function you have entered is not a square wave The sum of two cosine waves of the same frequency is another cosine wave of the same frequency In general the average value is 1/(b-a)∫^{b}_{a}f(x)dx You need to define the limits of the integral as that also determines the average value as much as the function itself This looks like a maths problem to me
The function you have entered is not a square wave The sum of two cosine waves of the same frequency is another cosine wave of the same frequency In general the average value is 1/(b-a)∫^{b}_{a}f(x)dx You need to define the limits of the integral as that also determines the average value as much as the function itself This looks like a maths problem to me