Hi,
I am struggling to understand why vd is split equally but phase is reversed at the two inputs of differential amplifier,
when vd is applied, the input at Q1 becomes: VBE + vd/2
and at Q2 it becomes: VBE-vd/2
why is that so?
please refer to page 6 of following link
http://www.ece.mtu.edu/faculty/goel/EE-4232/Diff-Amps.pdf for the diagram i am referring to
Thanks
humayun
I am struggling to understand why vd is split equally but phase is reversed at the two inputs of differential amplifier,
when vd is applied, the input at Q1 becomes: VBE + vd/2
and at Q2 it becomes: VBE-vd/2
why is that so?
please refer to page 6 of following link
http://www.ece.mtu.edu/faculty/goel/EE-4232/Diff-Amps.pdf for the diagram i am referring to
Thanks
humayun