I want to write a subckt which take pulse voltage as input and give sawtooth voltage as output. The sawtooth only appears where pulse voltage values are positive, and the rest of the time it will be zero.
An image file is attached that descrive input/output.
Any help or hints will be greate.

 

Use a behavioral current source that integrates a constant 1 as long as the input is greater than some small value ε>0.

 

Hi Papabravo,
I did integration and the netlist is as below:

********* sawtooth depending on input pulse******************************************************
.subckt conditional_sawtooth inputsignal outputsignal
.func sawtooth(inputsignal)=if(inputsignal>0, idt(inputsignal),0)
b1 outputsignal 0 V=sawtooth(V(inputsignal))
.ends output_interface


vin in 0 pulse(-1 1 0 1n 1n 25m 50m)
Xsaw in output conditional_sawtooth
.tran 200m
.end


The output is attached here but I want little modification in output. I need the output starts from 0 .

 

Hi Papabravo,
I did integration and the netlist is as below:

********* sawtooth depending on input pulse******************************************************
.subckt conditional_sawtooth inputsignal outputsignal
.func sawtooth(inputsignal)=if(inputsignal>0, idt(inputsignal),0)
b1 outputsignal 0 V=sawtooth(V(inputsignal))
.ends output_interface


vin in 0 pulse(-1 1 0 1n 1n 25m 50m)
Xsaw in output conditional_sawtooth
.tran 200m
.end


The output is attached here but I want little modification in output. I need the output starts from 0 .

The thing you should integrate is the unit step function. Looking at the description of the idt function:

B. Arbitrary Behavioral Voltage or Current Sources​

idt(x[,ic[,a]]) Integrate x, optional initial condition ic, reset if a is true.​

​

IMHO you should write something like this:

idt(1, 0, [a]) ; integrate the unit step with initial condition 0 as long as [a] is false. Stop the integration when [a] is true.​

​

Take a look at the buf(x) and inv(x) functions for easy ways to create a Boolean condition from an input signal.

​

 

Here is a quick demo I whipped up.

You can connect B1 & B2 in series to get a continuous sawtooth and you can change the duty cycle of V1 to unequal peaks on the sawtooth.
You can also do it with behavioral current sources, but they require additional components to convert the current into a voltage. If the amplitude is not to your liking, you can add a gain factor to the behavioral sources.

 

Thank you so much.