Sop=pos

Thread Starter

dhamphire

Joined Aug 2, 2008
3
Please help me..
Prove that:
BCD+ACD+ABD+ABC=(CD)(B+C)(A+C)(A)(A'B+D)

or i wast just wrong with the Kmapping?

thanks....
 

Ratch

Joined Mar 20, 2007
1,070
dhamphire,

Expanding out the SOP, we get the 5 logic values of 7,11,13,14,15 . The complement of the SOP are the missing 11 logic values which are 0,1,2,3,4,5,6,8,9,10,12 . Using the Quine-McCluskey method to simplify the 11 logic values we get A'B' + A'C' + B'C' + A'D' + B'D' + C'D' . This represents the complement of the given original expression. To reverse the complement, use DeMorgan's theorem to get (A+B)(A+C)(B+C)(A+D)(B+D)(C+D) in POS format.

Ratch
 
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