I have been asked to determine the equivalent circuit for a single phase transformer connection with the following measurements.

Given the transformer rating = (125/50 V)(1095 – 115) 50Hz

Short Circuit Test Measurements - LOW VOLTAGE side

voltage = 5.6V

current = 2.1A

power = 9.9W

Open Circuit Test Measurements - HIGH VOLTAGE side

voltage = 238.6V

current = 37.5mA

power = 2.625W

Open Circuit Test Measurements - LOW VOLTAGE side

voltage = 99.3V

current = 0.3A

power = 8.9W

My attempt

For Short circuit

θ = cos^(-1)(P/V*I)

=32.665°

Z = V/I <32.665°

= 2.7<32.665° = 2.2729 + j1.4572

(referred to primary side)

Re = 2.2729

Xe = j1.4572

For Open circuit

θ = cos^(-1)(P/V*I)

=72.939°

Y = I/V <72.939°

= 157.166<72.939° = 4.612 x10 ^(-5) + j1.5024 x 10^(-4)

(Referred to the Secondary)

Rc = 1/4.612 x10 ^(-5)

= 21.6 kΩ

Xm = 1/1.5024 x 10^(-4)

= 6.65 kΩ

a = Vo/Vin

= 238.6/99.3

= 2.4

Rc (Ref to Primary) = a^(2)* Rc

=124.416 kΩ

... Seems a little high

Xm (Ref to Primary) = a^(2)* Xm

=38.304 kΩ

These values for Rc' and Xm' seem way out. Where did I go wrong

Also If I have a resistive load at the output. How would I go about calculating the Power at the load?

Would I Refer the load to the Primary??? using R' = a^(2)*R ?

Thanks guys .... I'm pretty confused.