Go from step 1 and use DeMorgan's instead. Don't distribute the AB', that should put you on the right track.Originally posted by gino@Sep 17 2005, 04:35 AM
I am having trouble simplifying the following Boolean Expression in Sum of Products form:
AB' (C+D') + AB'C'D
= AB'C + AB'D' + AB'C'D
= ?
Can anybody help me please?
Thanks in advance.
[post=10401]Quoted post[/post]
I assume you apply DeMorgan's law to the first part of the equation?Originally posted by Brandon@Sep 18 2005, 02:03 AM
Go from step 1 and use DeMorgan's instead. Don't distribute the AB', that should put you on the right track.
[post=10404]Quoted post[/post]
Originally posted by gino@Sep 17 2005, 04:35 AM
I am having trouble simplifying the following Boolean Expression in Sum of Products form:
AB' (C+D') + AB'C'D
= AB'C + AB'D' + AB'C'D
= ?
Can anybody help me please?
Thanks in advance.
[post=10401]Quoted post[/post]
Originally posted by gino@Sep 18 2005, 12:03 AM
I didn't know the rule A + A'B = A + B. Is this derived from some Boolean Identities?
Not sure about using A + AB = A.
I follow your workings though. Thanks so much.
And we haven't covered Kmaps yet.
[post=10420]Quoted post[/post]
You can you the consensus theorem to simplify this expression. YZ is a redundant term. In the terms XY + X'Z, ignore the Xs (since there is X + X') and look at the other variables. The redundant term for these two is YZ. Similarly, if you had AB + A'C, the redundant term would be BC. I have found that this theorem is quite helpful. You can also add redundant terms to any expression in order to simplify it. Sometimes adding a redundant term will allow you to cancel another term, and then you can also cancel the redundant term as well.3) xy + x'z + yz
The best way is to simplify it.I'm trying to prove that the term AB is redundant in the function below.
Now we have.I dont seem to be getting any closer, am I?
Doing it after your solutionI am having trouble simplifying the following Boolean Expression in Sum of Products form:
AB' (C+D') + AB'C'D
= AB'C + AB'D' + AB'C'D
= ?
Can anybody help me please?
Thanks in advance.
Can anyone plz help me out to simplify boolean function
1) (A + B)' + (A' + B')'
2) y(wz' + wz) + xy
3) xy + x'z + yz
plzz do help me as my exams are supposed to start n plzz do tell me any site wherein i can refer n learn more bout system architecture.
thanks in advance
shradha
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