I was assigned the following problem for homeowork:

A'B'D+A'C'D+BD (a ' mark after a letter means a bar)

The directions read simplify the expression to an expression containing a minimum number of literals.

Here is my attempt, could someone please tell me if it is right? If I'm wrong, could you please post the correct way to do this?

A'B'D+BD+A'C'D (original function re-arranged)

(B+B')(A'D+D)+A'C'D

(1)(A'D+D)+A'C'D

A'D+D+A'C'D

A'D+A'C'D+D

A'D(1+C')+D

A'D(1)+D

D(A'+1)

D(1)

D

Thanks!