I found this site through researching and think this is the place to get a trusted answer... I do research here in the PNW, mostly at night with a pretty expensive 3rd gen. IR monocular which just eats up batteries. I would like to know 2 things.
1) Is it possible to remove the 4 AA batteries, and wire in a permanant power power supply.
2) What is the voltage of the 4 AA's..1.5 or added 6V and the amperage, to purchase the needed transformer/converter (DC of course).
The batteries stagger + and -, so I would assume I tie all the + and then all the - into the 2 +/- input leads.
Now I have 12VDC and Inverted 120VAC power to work with, but would really like to keep on the DC side of things...And of course if this is just a pie in the sky idea, please let me know for the IR device was not cheap...
Thanks allot in advance...
Steve
1) Is it possible to remove the 4 AA batteries, and wire in a permanant power power supply.
2) What is the voltage of the 4 AA's..1.5 or added 6V and the amperage, to purchase the needed transformer/converter (DC of course).
The batteries stagger + and -, so I would assume I tie all the + and then all the - into the 2 +/- input leads.
Now I have 12VDC and Inverted 120VAC power to work with, but would really like to keep on the DC side of things...And of course if this is just a pie in the sky idea, please let me know for the IR device was not cheap...
Thanks allot in advance...
Steve