Simple nodal analysis

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Quintilis_Telescope

Joined Oct 13, 2009
10
Hello. This one is so simple but Im having trouble using nodal analysis. Superposition would be easier but my prof wants me to use nodal.



Find the voltage at A. The answer is 5.7V ~, but I don't know how to get there.




Here are my equations I got that are wrong:

I3 = I1-I2

VA/1kΩ = ((15-VA)/1.197KΩ) - (VA/3.29kΩ)

and

I6 = I4-I5

VA/3.29kΩ = ((5V-VA)/1.197kΩ) - (VA/1kΩ)


Thankyou.
 

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The Electrician

Joined Oct 9, 2007
2,970
You only have one unknown, so you only need one equation.

The idea of the nodal method is to use Kirchoff's current law. The sum of the currents entering and leaving node A must be zero.

So, write an equation summing the currents in the 4 resistors to zero:

V/3290 + V/1000 + (V - 15)/1197 + (V - 5)/2212 = 0

Solve for V.
 
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