I'm studying for a test which will contain questions of how to obtain binomial coefficients, I understand the idea and can do it when the equation does not contain fractions but have trouble when it does contain fractions.
How does one go from:
(2x)^(9-k) (3/x)^k
to...
2^(9-k) 3^k x^(9-2k)
???
I'm sure it's an easy year 8 level problem, But I have not worked with fractions for a long time and seem to have forgotten it!
Thanks in advance!
PS:
For anyone actually interested in the binomial question, it is as follows:
Find the coefficient of x in the expansion of (2x + 3/x)^9
I have the answer if anyone wants it, I just don't understand the fractions part which I asked about above.
How does one go from:
(2x)^(9-k) (3/x)^k
to...
2^(9-k) 3^k x^(9-2k)
???
I'm sure it's an easy year 8 level problem, But I have not worked with fractions for a long time and seem to have forgotten it!
Thanks in advance!
PS:
For anyone actually interested in the binomial question, it is as follows:
Find the coefficient of x in the expansion of (2x + 3/x)^9
I have the answer if anyone wants it, I just don't understand the fractions part which I asked about above.