I have 2 cash drawers, one is using an epson receipt printer wheras the other is using a serial port. The one with the serial port used to be a receit printer type but has been modified. I am looking to make the same modification to the one currently using the printer. Unfortunately I have a partial template as the person who made the circuit board put half the board under a ton of glue. below are all the details of the circuis I can see and hopefully someone can "fill in the blank"
Visible Components:
9 pin serial
12v power adaptor
Solenoid/electro magnet
Large polarized capacitor, Value unknown, assuming 470uf
Diode (I think)
Everything between the dashed lines are connected together
-------------------------------
Serial port pins
4(Data terminal ready)
8(Clear to send)
6(data Set Ready)
White wire, goes to unvisible connection
------------------
Pin 5 (ground)
- side of diode
- side of solenoid
To unvisible location
-------------------------------
VCC -
Capacitor -
Unvisible location
--------------------------------
VCC +
Capacitor +
Diode +
Solenoid +
----------------------------------
I am quite advanced when it comes to logic design, but I have difficulty when other components are involved.
The way I figure the circuit works is like a relay. When the serial port triggers, it discharges the capacitor to the solenoid to open the drawer. The solenoid requires somewhere around 12-22 volts but the serial port only generates 5v.
any help would be greatly appreciated.
Thank you
Marc
Visible Components:
9 pin serial
12v power adaptor
Solenoid/electro magnet
Large polarized capacitor, Value unknown, assuming 470uf
Diode (I think)
Everything between the dashed lines are connected together
-------------------------------
Serial port pins
4(Data terminal ready)
8(Clear to send)
6(data Set Ready)
White wire, goes to unvisible connection
------------------
Pin 5 (ground)
- side of diode
- side of solenoid
To unvisible location
-------------------------------
VCC -
Capacitor -
Unvisible location
--------------------------------
VCC +
Capacitor +
Diode +
Solenoid +
----------------------------------
I am quite advanced when it comes to logic design, but I have difficulty when other components are involved.
The way I figure the circuit works is like a relay. When the serial port triggers, it discharges the capacitor to the solenoid to open the drawer. The solenoid requires somewhere around 12-22 volts but the serial port only generates 5v.
any help would be greatly appreciated.
Thank you
Marc
