# Simple Circuit... Source Transformation

Discussion in 'Homework Help' started by cursed, Oct 3, 2010.

1. ### cursed Thread Starter New Member

Oct 3, 2010
2
0
Solve for ix in the following circuit using source transformation:

So here's what I did:

I'm confused how I find ix now, unless I did something wrong...? Maybe I'm supposed to convert the current source to voltage? Can someone help ASAP? Thanks.

2. ### Georacer Moderator

Nov 25, 2009
5,151
1,266
Firstly, you have calculated wrong the value of the resistor. When two resistor end up being parallelly connected, in order to find their equivalent you don't add them. The equivalent is $R_{eq}=\frac{R_1\cdot R_2}{R_1 +R_2}$.
Addition only works for resistors connected in series.

Also, when two current sources are connected in parallel, they can be replaced with a single current source with double the current rating.