Hello! I need some help understanding this signal the signal is x(t)u(1-t) I understand that u(1-t){0 t>1, 1 t<=0} But I do not understand why it's zero at -1. Is it because x(t){0 t<0, 1 t>=0}
You are multiplying by a term called (1-t) Multiplication by zero is always zero. what is the value of 't' when the term (1-t) is zero?
Is this question about finding the signal x(t) based on the graph of x(t)u(1-t)? Is x(t) an uknown? If so remember that u(1-t) is 0 for t>1 and 1 for t<1; it is different from what you wrote. I guess your job is to find x(t) based on that.