Series Resonance Help

Thread Starter

trav

Joined Dec 8, 2011
7
Connect the 50 Ω output from the function generator to the oscilloscope input and establish a sine wave on the oscilloscope with the following characteristics:
a. f = 100 Hz, Vmax = 500 mV
Disconnect the output of the function generator from the oscilloscope and apply it to your circuit.

Giving me the result:

f(hz) Vr(V) vc(V) vl(V)
100 0.96 0.65 0.06
150 0.13 0.63 0.08

It then asks me to use these results to calculate the following parametersfor 100 and 150hz:

I (A)
XL (Ω)
XC (Ω)
Z (Ω)




How do i do this?
 
Last edited:
Ohms law my friend...and depending on whether you know the values of capacitance, inductance and resistance and have a basic knowledge of complex numers this is how it is calculated

Vr + Vc + Vl = total voltage (Vt)

Xl = jwl=2*pi*f*l
Xc=jwc=2*pi*f*c
Z=R+(jwl-jwc)

It = Vt/Z
 

crutschow

Joined Mar 14, 2008
24,380
You only need ohms law to calculate the various impedances. Since you know that the currents are the same in all devices for a series circuit, it's a simple matter to calculate each impedance knowing the current through, and the voltage across, each impedance.
 

Thread Starter

trav

Joined Dec 8, 2011
7
Would i be right in saying:

1. I v/r 0.0957/100

2. Xl = 2pi x f x l

3. Xc = 1/2pi x f x c

4. Z = √rsquared+(Xc-Xl)squared

5. tan-1(Xc-Xl)/R

I think im right here but would like some clarification especially with the first one of all things lol
 

Adjuster

Joined Dec 26, 2010
2,148
Would i be right in saying:

1. I v/r 0.0957/100

2. Xl = 2pi x f x l

3. Xc = 1/2pi x f x c

4. Z = √rsquared+(Xc-Xl)squared

5. tan-1(Xc-Xl)/R

I think im right here but would like some clarification especially with the first one of all things lol
In your first post, you had Vr(V)=0.96. Now it seems to be 0.0957. Which is it to be?
 

Thread Starter

trav

Joined Dec 8, 2011
7
0.096 sorry my mistake but thats not really my issue here. More intrested in the formulas being correct.
 
Last edited:

Wendy

Joined Mar 24, 2008
21,938
After you get it sorted out in your head figure out the voltage the components are dropping. I love to give this question to beginners, because the results are so surprising.
 

t_n_k

Joined Mar 6, 2009
5,447
Interestingly, the experimental procedure seemed to make no directive to the student to adjust the generator frequency in order to find the series resonance condition.

Is the OP aware of the measurement indication(s) of when resonance has actually occurred?
 
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