Hi, I was hoping someone would suggest how to approach this voltage division inquiry with a series circuit of resistors. Each time I turn the rotary switch (12 positions) the output would be 50mV less than the position before.
I was thinking this might be a stepped attenuator.
Or maybe a window comparator as far as the math is concerned?
I see example circuits that monitor the voltage of your car battery and display it on a LM3914 with LED's as indicators. The many trigger voltages are set by the designer with a string of resistors and then sets up a comparator to pit against the trigger points.
For example: I start with 2.0v DC that would be at the top of the series string of resistors.
1st rotary position = 2.000v then next would be 1.950v then 1.900v etc.
In the car battery examples, the current value is not mentioned that I can decipher.
I am hoping the current would not matter with my inquiry because I would like to use this divider on any value of voltage as long as I can drop 50mV. I would calculate resistor wattages when appropriate.
So I would be looking for the last (12th) position on the rotary to output 0v.
Thank you for any suggestions and help you may offer.
I was thinking this might be a stepped attenuator.
Or maybe a window comparator as far as the math is concerned?
I see example circuits that monitor the voltage of your car battery and display it on a LM3914 with LED's as indicators. The many trigger voltages are set by the designer with a string of resistors and then sets up a comparator to pit against the trigger points.
For example: I start with 2.0v DC that would be at the top of the series string of resistors.
1st rotary position = 2.000v then next would be 1.950v then 1.900v etc.
In the car battery examples, the current value is not mentioned that I can decipher.
I am hoping the current would not matter with my inquiry because I would like to use this divider on any value of voltage as long as I can drop 50mV. I would calculate resistor wattages when appropriate.
So I would be looking for the last (12th) position on the rotary to output 0v.
Thank you for any suggestions and help you may offer.