Hello guys, I need some help with this HW problem.
The problem got a current source (Is), 5ohm resistor, 8mH inductor and a 2mF capacitor. All the components are in parallel with each other respectively. The current for the Inductor was given as
IL= 10(1-e^-625t)A ( L-current arrow flows top to bottom)
1) First question is to determine the expression for V across the capacitor. ( + at the top node and negative and bottom)
My solution was Vc = 1/c ∫10(1-e^-625t) dt
=1/2mF ∫10(1-e^-625t) dt
2) Question 2 is determine the expression for the current through the capacitor
I know Ic= C dv/dt
Therefore Ic = 2mF [ 10(1-e^-625t) dt] ......is this right? I cant think of anything else :-(
3) Last question is to determine the expression for (Is) ( current source)
in the schematics, (Is) is flowing from the bottom to the top node.
How do I go about getting Is :-( ?
Thanks in advance.
The problem got a current source (Is), 5ohm resistor, 8mH inductor and a 2mF capacitor. All the components are in parallel with each other respectively. The current for the Inductor was given as
IL= 10(1-e^-625t)A ( L-current arrow flows top to bottom)
1) First question is to determine the expression for V across the capacitor. ( + at the top node and negative and bottom)
My solution was Vc = 1/c ∫10(1-e^-625t) dt
=1/2mF ∫10(1-e^-625t) dt
2) Question 2 is determine the expression for the current through the capacitor
I know Ic= C dv/dt
Therefore Ic = 2mF [ 10(1-e^-625t) dt] ......is this right? I cant think of anything else :-(
3) Last question is to determine the expression for (Is) ( current source)
in the schematics, (Is) is flowing from the bottom to the top node.
How do I go about getting Is :-( ?
Thanks in advance.