After proforming a test at college, I am left to write a report about it. I am now stuck and need help explaining when when you double R-L-C in turn in the circuit you have a larger or smaller bandwidth.

RESULTS Resonant frequency Hz Amplitude at resonance
dB Bandwidth Hz
f2 - f1
R = 80 ohms
L = 40 mH
C = 400 nF 1.254K -38.191 321
Resistance doubled
R = 160 ohms
L = 40 mH
C = 400 nF 1.254K -44.142 645.761
Inductance doubled
R = 80 ohms
L= 80mH
C = 400nF 887.692 -38.212 161.742
Capacitance doubled
R = 80 ohms
L = 40 mH
C = 800nF 887.692 -38.18 324.985

These are the results I gained from the tests, I need to odserve and explain why these results have occrued.

 

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