Hi everyone.
I,m studing RLC circuits and i have two confusions i would like to understand.
1.in series RLC circuit the book says that the final voltage at the
capacitor (at t=∞) is same as the source...why? is it because C behave
as Open ?!! why don't R dissipate some power and thus draws voltage
so that Vc not equal to Vs and thus current flows.
2.For the circuit attached..the switch has been closed for a long time ..OK.
t<0
before it is opened..are theree two short circuits one is the switch and the other is due to L because it behave as SC at t=∞..how can i calculate value of current"do I simply divide by two"?
t>0
how do C and L behave after the switch opens?
Waiting your help
I,m studing RLC circuits and i have two confusions i would like to understand.
1.in series RLC circuit the book says that the final voltage at the
capacitor (at t=∞) is same as the source...why? is it because C behave
as Open ?!! why don't R dissipate some power and thus draws voltage
so that Vc not equal to Vs and thus current flows.
2.For the circuit attached..the switch has been closed for a long time ..OK.
t<0
before it is opened..are theree two short circuits one is the switch and the other is due to L because it behave as SC at t=∞..how can i calculate value of current"do I simply divide by two"?
t>0
how do C and L behave after the switch opens?
Waiting your help
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