My work are written below. can anyone help to confirm if the answer i have is the correct one.

Question:

The 35 Vrms ac voltage Vs is derived from an ideal 60Hz main

transformer. It is connected to a half-wave rectifier and a

220μF capacitor to form a dc power supply. If the load RL

draws an average current 0.15A, determine:

i. the peak-to-peak capacitor ripple voltage

**Answer : Vr(pp) = 5.6V**

ii. the average or dc voltage across the load

**Answer : Vdc = 43.82V**

iii. the percentage ripple factor, %r.

**Answer : 12.8%**

__iii) my solution steps__with formular --> %r = [Vr(rms) /Vdc] x 100%.

I calculated Vr(rms) = Idc/ (4√3 (60)(220u) = 1.64V

and Vdc = Vm - (Idc/2fC) =43.82V

So, the %r = 1.64 / 43.82 (100%) = 3.74%

Thanking you guys in advance!