just want to know how to create a circuit for LM3914 within a range of 4.7V to 5.9V, the 10 LEDs should illuminate when the input voltage is at 5.9V and no LEDs will illuminate at 4.7V input, i had already read the data sheet of LM3914 from national instrument but can't have any idea how to construct, thanks,

 

Check this link
http://www.national.com/ds/LM/LM3914.pdf
construct the circuit and then post back.

 

On the link Rifaa posted, look at the Typical Application circuit on page 2.

For the resistor values,
R1: 1,270 Ohms
R2: 4,370 Ohms
You will also need another resistor between pin 4 and ground; a value of 39,167 Ohms.

These values are approximate, and based on the difference between pins 7 and 8 being 1.25v, and the internal resistive divider measuring exactly 10k Ohms.

[eta]
You can't buy resistors with those exact values, but you can use resistors in series and/or parallel to get very close.
Here is a handy online calculator for series/parallel resistance:
http://www.qsl.net/in3otd/parallr.html
Bookmark that page.
For example, if you select E24 values (commonly available) and ask for 1270 Ohms, you'll get output like:
910 + 360 = 1270 (0 %) (This means a 910 Ohm and a 360 Ohm resistor in series to get 1270 Ohms, 0% error)
1600 || 6200 = 1271.795 (0.141 %) (This means a 1.6k and 6.2k resistors in parallel for 1271.795 Ohms; 0.141% error)

You will need to use a supply of at least 8v.

 

I still wonder why odd values are used in data sheets

 

got it, its the external resistor combination must be set for the Ref low (4) and Ref high, im goin to reconstruct my old circuit, thanks a lot,