# resistor voltage drop

Discussion in 'General Electronics Chat' started by willdr, Aug 14, 2008.

1. ### willdr Thread Starter New Member

Aug 14, 2008
2
0
how is the voltage drop across a single resistor calculated? In a simple E Mosfet circuit from where are the measurements for Vg and Vd taken?

2. ### SgtWookie Expert

Jul 17, 2007
22,201
1,807
Ohm's Law:
E = sqrt(PR), or Voltage = the square root of (Power in Watts x Resistance in Ohms)
E = P/I, or Voltage = Power in Watts/Current in Amperes
E = IR, or Voltage = Current in Amperes x Resistance in Ohms
The reference is the source. It's usually specified (respectively) as Vgs and Vds or Vdss.

3. ### willdr Thread Starter New Member

Aug 14, 2008
2
0
I have 15v Vdd and one resistor 2.7 Kohms gong into a E mosfet and I measure 3.544v for Vd but have not been able to calculate it.

4. ### SgtWookie Expert

Jul 17, 2007
22,201
1,807
Why don't you post a schematic of your circuit?
That's much easier than trying to describe it.
As of this moment, I have no clue as to what your Vgs is, what MOSFET you're using, or even if it's N-ch or P-ch.

Last edited: Aug 14, 2008