resistor voltage drop

Thread Starter

willdr

Joined Aug 14, 2008
2
how is the voltage drop across a single resistor calculated? In a simple E Mosfet circuit from where are the measurements for Vg and Vd taken?
 

SgtWookie

Joined Jul 17, 2007
22,210
how is the voltage drop across a single resistor calculated?
Ohm's Law:
E = sqrt(PR), or Voltage = the square root of (Power in Watts x Resistance in Ohms)
E = P/I, or Voltage = Power in Watts/Current in Amperes
E = IR, or Voltage = Current in Amperes x Resistance in Ohms
In a simple E Mosfet circuit from where are the measurements for Vg and Vd taken?
The reference is the source. It's usually specified (respectively) as Vgs and Vds or Vdss.
 

Thread Starter

willdr

Joined Aug 14, 2008
2
I have 15v Vdd and one resistor 2.7 Kohms gong into a E mosfet and I measure 3.544v for Vd but have not been able to calculate it.
 

SgtWookie

Joined Jul 17, 2007
22,210
I have 15v Vdd and one resistor 2.7 Kohms gong into a E mosfet and I measure 3.544v for Vd but have not been able to calculate it.
Why don't you post a schematic of your circuit?
That's much easier than trying to describe it.
As of this moment, I have no clue as to what your Vgs is, what MOSFET you're using, or even if it's N-ch or P-ch.
 
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