# RECTIFIERS

Joined Feb 20, 2006
2
hi new to the website and rely need some help .....

a half wave rectifier operatin from a 50hz 24volt AC supply is connected to a 100 Ω load
caluclate the value of the smoothing capacitor required to maintain a peak to peak voltage ripple at 2volts

#### dragan733

Joined Dec 12, 2004
152
Originally posted by helpmeplease@Feb 20 2006, 11:50 PM
hi new to the website and rely need some help .....
a half wave rectifier operatin from a 50hz 24volt AC supply is connected to a 100 Ω load
caluclate the value of the smoothing capacitor required to maintain a peak to peak voltage ripple at 2volts

[post=14222]Quoted post[/post]​
U ≈ Umax- ∆ U/2=Umax- ∆ Q/(2C)=Umax-I/(2Cf)=Umax-U/(2RCf)
U ≈ Umax-U/(2RCf)
from here
2RCf ≈ U/(Umax-U)
C ≈ U/( ∆ URf), where ∆ U=2(Umax-U)
C ≈ 24/(2*100*50)=2400 μ F
C ≈ 2400 μ F

Regards