I just wanted confirmation on this one:
http://img8.imageshack.us/img8/8641/scan0058vzn.jpg
Supposed to just calculate the time constant RC
I think it goes something like this:
After a long period of time the current source is going to act like an open-circuit and thus eliminate the resistor that is in series with it.
After a long period of time the voltage source acts like a short circuit and also effectively gets rid of the resistor in parallel with it.
The effective circuit after a long period of time and thus my RC calculation is simply based off the capacitor in series with only the 1k ohm resistor to the upper right of the capacitor (since the other two are gone).
RC = 1000*(1*10^-6)
correct?
http://img8.imageshack.us/img8/8641/scan0058vzn.jpg
Supposed to just calculate the time constant RC
I think it goes something like this:
After a long period of time the current source is going to act like an open-circuit and thus eliminate the resistor that is in series with it.
After a long period of time the voltage source acts like a short circuit and also effectively gets rid of the resistor in parallel with it.
The effective circuit after a long period of time and thus my RC calculation is simply based off the capacitor in series with only the 1k ohm resistor to the upper right of the capacitor (since the other two are gone).
RC = 1000*(1*10^-6)
correct?