Hello. I'd like to get some confirmation on a question. It's about the formula that describes current through capacitors. i = C.dV/dt .So let's start with C. As you increase the capacitance, it takes more and more time for the capacitor to charge to a specific voltage and thereby by increasing C you effectively decrease the potential difference between the Source voltage(i'll call this one Vs) and the capacitor voltage Vc and this leads to a bigger instantenious current through the capacitor. Now the rate of change of the voltage dV/dt.
The picture i tried to upload is a potentiometer with a capacitor connected to it. The potentiometer can move up to deliver more Voltage to the capacitor. Now if we assume that Vc at first ist 0v and we begin to move the wiper up, increasing the voltage, the faster we move it from p.A to p.B the less time would the current have had to flow, thus less charge would have exited the capacitor and less voltage would the capacitor have accumulated for that short period of time dt. Thus when the final Vs voltage across the capacitor is established, the potential difference Vs - Vc would be greater than if the voltage was changed with a slower rate, and the current that will flow through the capacitor will be greater too.
Is that right?
The picture i tried to upload is a potentiometer with a capacitor connected to it. The potentiometer can move up to deliver more Voltage to the capacitor. Now if we assume that Vc at first ist 0v and we begin to move the wiper up, increasing the voltage, the faster we move it from p.A to p.B the less time would the current have had to flow, thus less charge would have exited the capacitor and less voltage would the capacitor have accumulated for that short period of time dt. Thus when the final Vs voltage across the capacitor is established, the potential difference Vs - Vc would be greater than if the voltage was changed with a slower rate, and the current that will flow through the capacitor will be greater too.
Is that right?