Random walks probability

Thread Starter

boks

Joined Oct 10, 2008
218
For a random walk of 10 000 steps, what is the chance of ending up exactly where we started?


(10 000 choose 5000)/2^10000, right? This calculation can't be done on a calculator, so I use Stirling's formula:

ln M! = M lnM - M + 0.5 ln (2*pi*M), knowing that

(10 000 choose 5000) = 10 000!/(5000! * 5000!)

But I also need a way to approximate 2*10 000. How do I do that?
 
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