I'm not seeing how you get your equations.ok the following circuit has the exact circuit i have described above. I am having trouble trying to get the correct answer which is Vo = 22.34.
View attachment 30969
This is what i have done
1st equation using KCL
528=24V1 + V2
2nd Equation using KVL
-4i + 2Vo + V2 = V1
where i = V1 - 2Vo-V2
where V1 = Vo
-4(V1-2V1-V2)+2V1+V2=V1
7V1+5V2=0
V1=-5V2/7
sub back into 1st equation and we get
528 = -120V2/7 + V2
3696 = -113V2
V2 = -32.707
V1 = (-5*-32.707)/7
So V1=Vo=23.36volts