- Joined Mar 1, 2009
I've never toyed really with a constant current device. I'm understanding that the MOSFET Q1 will dissipate power based on (Vin - Vdrop at load) times current. Question is, if there's a larger than nominal voltage left over that Q1 has to absorb, can I put a resistor in series with my load to drop a couple more volts in an effort to reduce the power dissipation of the MOSFET? I'm assuming I can, but assumptions have gotten me in trouble before.
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