# question about circuit with 6 resistors

Discussion in 'Homework Help' started by becca02, Jan 28, 2009.

1. ### becca02 Thread Starter Member

Jan 28, 2009
10
0
Okay, im stuck... how do i find the voltage drops along each resistor?

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2. ### jahmal New Member

Jan 27, 2009
1
0
9= R1 I1 + R2 I1 - R2 I2
0= R2 I2 + R3 I2 + R4 I2 - R2 I1 - R4 I3
0= R4 I3 + R5 I3 + R6 I3 - R4 I2

then you got to solve it matricial way and you get the I(1,2,3) current, and after you use Ohm law(U=RI) to solve each voltage drop along each resistor..

hope I can be useful

3. ### becca02 Thread Starter Member

Jan 28, 2009
10
0
hmmm ... I think that's my problem.. i don't know how to get the current values... any suggestions?

4. ### The Electrician AAC Fanatic!

Oct 9, 2007
2,610
466
Calculate R5 in series with R6, and then that equivalent (E1) in parallel with R4.

Calculate that equivalent (E2) in series with R3, and then that in parallel with R2.

Calculate that equivalent (E3) in series with R1 and you can then get the current from the battery.

Knowing the current from the battery, which also passes through E3, you can calculate the voltage at the node where R1, R2 and R3 are connected.

Then you can calculate the current through R2. The current through R3 is equal to the battery current minus the current through R2.

Continue to the end.

5. ### Cabwood Member

Feb 8, 2009
20
0
For a really simple 2-resistor potential divider, you can calculate the voltage dropped across each one without ever knowing or thinking about the current. The same goes for more complex systems like this.

The electrician is right - you start by simplifying the circuit so that it consists of just two resistors - R1 in series with whatever the combined resistance of R2, R3, R4, R5 and R6 is.

Then you have a simple 2-resistor potential divider for which you can calculate the voltage across R1. Work on from there for the remaining resistors.

6. ### mik3 Senior Member

Feb 4, 2008
4,846
69
Which circuit analysis theorems do you know?

One way to do it is to combine all the resistors in one,find the total current and then start extracting the resistors again and use the voltage and current divider rule to find what you want.