Quantization Gain Problem

Thread Starter


Joined May 7, 2013
Quantization noise power is proportional to d2 / 12 where d is the step size in volts. What will
be the gain in Signal to Quantization Noise Ratio (SQNR) of going from 4 bit encoding to 8 bit
encoding? Express your answer in dB.

I know we have to assume v= voltage range. But then idk what to do ?


Joined Feb 19, 2010
There are several ways to calculate SQNR.

In this case you want the formula that relies on bits:
SQNR in dB=6.02*B dB
B is number of bits.

1) Solve for 4 bits.
2) Solve for 8 bits.
3) Find the difference.

This assumes that the signal is full-scale uniformly distributed random signal.

This is from my textbook. Software Radio: A Modern Approach to Radio Engineering, Jeffrey H. Reed.