I have attached my work on another problem involving superposition. It involves a Is and Vs and is asking me to find Ir3. Help is much appreciated!
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You're correct again. I guess I'm going a little too fast calculating the answer on some of these problems. Thanks again!While calculating I (killing Vs) entering at B the resistance in the denominator should be the sum of total resistance.I think you have made a mistake there.
The answer is 1.6 mA and that is what I got when correcting the value of the denominator to 852.5 ohms when calculating for I entering pt. B.What is the answer given in the book?
hgmjr
Below is the Millman's Theorem expression for the voltage across the 680 ohm resistor as well as the series combination of the 330 and the 470 ohm resistor.
\[\LARGE V_{\large x}\,=\,\frac{\frac{20}{220}\,+\,0.1}{\frac{1}{220}\,+\,\frac{1}{680}\ +\,(\frac{1}{330\,+\,470})}\]
To obtain the current in R3, all that is needed it to divide Vx by 800
\[{\Large I}_{R3}\,=\,\frac{V_X}{800}\]