power of sinusoid signal

Thread Starter

screen1988

Joined Mar 7, 2013
310
I am reading an article about ADC. This part is confusing.
If the analog input is a sinusoid with amplitude Vref/2 (peak-to-peak Vref), its total power is equal to Vref/ 8.

P = U^2/R = (Vref/2√2)^2 /R = Vref/(8R)
Why is R omitted here? I mean that why R = 1.
 

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Ron H

Joined Apr 14, 2005
7,063
I'm assuming it's because SNR is the ratio of two powers.
Psig=Vsig^2/R
Pnoise=Vnoise^2/R
Psig/Pnoise=((Vsig^2)/R)/((Vnoise^2)/R)
Psig/Pnoise=Vsig^2/Vnoise^2

The R cancels out, so it is irrelevant.
 

Thread Starter

screen1988

Joined Mar 7, 2013
310
Thanks, that makes sense!
I want to ask one more question.
SNRp means "peak signal to noise ratio". Why we need to include "p" here?
Because this is a ratio between two signals, the ratio doesn't depend on if is peak or root mean square?
 
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