A 120V, 60Hz source is applied across an inductive load of (100 + j700)Ω. What is the power factor of the load? What must be the size of the capacitor that can be placed in parallel with the load in order to improve the power factor to 0.95 lagging?
See figure attached for my attempt, I can't figure out what the impeadance of the capictor has to be.
I'm thinking I could do,
\(Z_{new} = Z_{c} // Z_{l} = x +jy\)
and select C such that,
\(arctan(\frac{y}{x}) = 18.195^{o}\)
but the math and algebra gets pretty ugly taking this approach.
Is there another way?
See figure attached for my attempt, I can't figure out what the impeadance of the capictor has to be.
I'm thinking I could do,
\(Z_{new} = Z_{c} // Z_{l} = x +jy\)
and select C such that,
\(arctan(\frac{y}{x}) = 18.195^{o}\)
but the math and algebra gets pretty ugly taking this approach.
Is there another way?
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