ahhh I see now, but after changing I just solve for all three unknowns and use the current that is (I2) as (I).Correct?

Yes. Your I2 is the same as I.

However, be aware of the sign. I2 is clockwise, it is part of the procedure to assume that clockwise current is positive and counter clockwise current is negative. So when you find I2, you have two answers, the magnitude of the current and the direction of the current. Magnitude is represented by the number. Direction is represented by the sign.

Since I is in opposite direction from I2, this means that I will have same magnitude as I2, but different sign because it is in opposite direction.

Example 1.
Let us say that I2 is +2 A. Then I will have same magnitude, 2, but different sign, -. So I=-2 A.

Example 2.
Let us say that I2 is -3.5 A. Then I=+3.5 A.

 

ahhh I see now, but after changing I just solve for all three unknowns and use the current that is (I2) as (I).Correct?

Close, but not quite. And this is why it is very important to mark on the diagram as much information as possible. Consider the following diagram and reconsider your answer.

 

Yes. Your I2 is the same as I.

Only if you consider +3.5A to be the same as -3.5A or +12V to be the same at -12V.

I2 and I are two different symbolic currents that are related through the equation

I = -I2

It's fine to think of a current has having a magnitude and a direction and think of those as two separate pieces of information, but even then I2 is not the same as I. In order to be the same, they have to have both the same magnitude AND the same direction.

 

I don't know what I would do w/o this forum lol...Prolly struggle more. But I will keep this in mind.So when I do my calculations, I make note of which way IM saying the current is going saying whether or not the current is + or - in my calculations is up to me as long as I know what direction the current in the original diagram is labeled. BTW, just to make sure I get this, current prefers to move from High(+) to Low(-) like a stream of water but if a current is flowing upstream(opposite direction) it'll have the same energy as the current rushing downstream just a different direction.