The confusing part is that there is no ammeter nor voltmeter in the circuit.
At the top, "E" is your battery or voltage source.
At the bottom is your potentiometer.
The lower the value of the resistance of the potentometer, the more current will flow in the circuit, which could be measured using an ammeter inserted into the wire on either side of the current loop.
Since in this schematic, the potentiometer is also RL (load resistor), all voltage "drop" will be across the resistor.
Do you mean INSTEAD of the bottom line in the circuit?Consider that we have a voltmeter placed at the bottom line of the circuit, then what do you say about it?
Then the battery current will be constant, and the voltmeter will read from zero to the value of E as you move the wiper from full left to full right.No, not instead of bottom line, but in the bottom line.
You mean this circuit is not a potentiometer?The circuit is a smoke producer when the resistance of the pot is turned down. It has nothing to limit the max amount of current when the resistance is turned down. The pot might even light up for a moment.
With the voltmeter in the bottom line, it is a potentiometer, not a rheostat, because voltmeters ideally draw no current.The circuit is a smoke producer when the resistance of the pot is turned down. It has nothing to limit the max amount of current when the resistance is turned down. The pot might even light up for a moment.
What are you wanting to do with a potentiometer? If you connect the wiper to either battery terminal, the pot will be destroyed when you turn the wiper all the way to the other end. Furthermore, when the wiper is connected to one end of the resistance element, the circuit is properly called a rheostat. If you leave the wiper disconnected, it forms a voltage divider between the two ends of the resistive element, and is a true potentiometer.And basiclly my problem is the attachment of wiper of p. meter with the negative terminal in the circuit.Because my limited knowledge suggests that it should be joined at opposite terminal(+ ve).
I don't know how we can explain it any better. Several people have given you really good explanations. I suggest you reread all of them.In the link i have given above you can see the potentiometer, i am just asking that there is one node only in that schematic, if we simply put that single node on the upper edge(just as it was on the lower edge) then what would happen? If you see my schematic you will notice only one change between my schematic and the schematic of the e-book i.e. which i have discussed above.
I think by doing this, we destroy true functioning of p. meter as potential divider.
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